1->
void fn()
{
	 static int i = 10;
	 printf("%d ", ++i);
}

int main()
{
  	fn();
  	fn();
}

A) 10 10
B) 11 11
C) 11 12
D) 12 12

Ans : C



2->
int main ()
{
	int a[4] = { 25, 16 };
	printf ("%d %d", a[0] & a[1], a[1] | a[3]);
}

A) Syntax error because of invalid operator symbol
B) 16 25
C) 25 0
D) 16 16
E) Syntax error because of invalid array initialisation

Ans : D



3->
int main()  
{
	printf("%d%d%d", sizeof(3.14f), sizeof(3.14l));
}

A) 4160
B) 844
C) 3284
D) Error

Ans : A


 
4->
int main()


{

 
	int x[10] ={1,2,3,4,5} ;

 	printf("%d %d %d", x[2], 2[x],x[5]);


}

Give output or explain if error:

Ans : 3 3 0



5->
int N = 10; 
int main() 

{ 
 
	static int x = 1;

	if (printf("%d ",x) && x++ < N && main())
	{
 		return 1;
	}
	return 0;

}
Give output or explain if error:

Ans : 1 2 3 4 5 6 7 8 9 10




------------------------------Bonus Question------------------------

6->
int main()
{
	static int i;
	for(i++;++i;i++)
	{
		printf("%d ", i);
		if(i == 6) 
		break;
	}
	return 0;
}

A. 2 4
B. No output
C. 2 4 6
D. Program never ends

Ans : C